[機經] #24 殘題 --> GWD 原題
完整圖文:
https://www.facebook.com/groups/DonzGMAT/811299325592372
24. 一個數(不記得是不是n)可以被3除餘1,n是非負整數,並且等於2^n。
最後求什麼忘了,就讓它殘著吧……會有更多的狗
(GWD 原題)
For a nonnegative integer n, if the remainder is 1 when 2^n is divided
by 3, then which of the following must be true?
I. n is greater than zero.
II. 3^n = (-3)^n
III. √2^n is an integer.
A. I only
B. II only
C. I and II
D. I and III
E. II and III
Answer: E
2^0 ÷3…………….1
2^1 ÷3……………..2
2^2 ÷3…………….1
2^3 ÷3……………..2
由循環可得,2^n ÷3……………1 --> n is even
I. n is greater than zero. --> n 可以為 0 could be wrong
II. 3^n = (-3)^n --> must be true
III. √2n is an integer. --> 如果 n 是偶數,2n 則為平方數
√2n is an integer, must be true
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※ 編輯: dounts (1.161.151.31), 03/19/2015 23:41:39
→
03/26 20:07, , 1F
03/26 20:07, 1F
推
03/26 20:09, , 2F
03/26 20:09, 2F
2^4 = 16, 2^6 = 64 都是平方數呀
※ 編輯: dounts (180.176.118.67), 03/27/2015 23:57:48
→
03/28 18:07, , 3F
03/28 18:07, 3F
→
03/28 18:08, , 4F
03/28 18:08, 4F
→
03/28 18:09, , 5F
03/28 18:09, 5F
→
03/28 18:09, , 6F
03/28 18:09, 6F
打錯 是根號2^n
※ 編輯: dounts (1.161.152.28), 03/30/2015 10:29:22