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難得沒事來騙騙P幣好了,. 設D(x,y,z),由四邊等距:. x^2 + y^2 + z^2 = (x-1)^2 + (y-1)^2 + (z-√2)^2 = (x-2)^2 + y^2 + z^2 = 4. => 2x-1 + 2y-1 + 2√2z-2 = 0. 4x-4 = 0. x^2 +
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一樣騙P幣※ 引述《tobe6104 (拖拖拖拖比)》之銘言:. 難得沒事來騙騙P幣好了,. 設D(x,y,z),由四邊等距:. x^2 + y^2 + z^2 = (x-1)^2 + (y-1)^2 + (z-√2)^2 = (x-2)^2 + y^2 + z^2 = 4. => 2x-1 + 2
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