Re: 隱函數微分
x√y = 2
d d
→ ---- ( x√y ) = ---- ( 2 )
dx dx
x dy
→ √y + ------ ‧ ---- = 0
2√y dx
dy -2y
→ ---- = -----
dx x dy
-2‧----‧x - 1‧(-2y)
d^2y d dy d -2y dx
→ ------ = ---- ( ---- ) = ---- ( ----- ) = ----------------------
dx^2 dx dx dx x x^2
-2y
-2‧-----‧x + 2y
x 6y
= ----------------- = -------
x^2 x^2
_______#
有錯誤的地方請指正 謝謝 :D
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