[理工] [工數]-pde
d^2 u d^2u
---- = 9 ---- - e^-x 0<x<4 t>0
dt^2 dx^2
BC: u(0,t)=u(4,t)=0 t≧0
du(x,0)
IC: u(x,0)=sin(πx) , --------=0 0<x<4
dt
這題我用sin展開
算到
2 2 -4 n
d^2 nπ (4-4e (-1) )*64
------bn = -9----bn - -----------------------------------------
dt^2 16 nπ*(16-(n^2)(π^2))*3(n^2)(π^2)
答案超醜的..
請問有人能算算看嗎?
沒算過過程那麼醜的pde..
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