Re: [理工] [工數]-拉氏!!!~~~~~~~~~~~~~~~~
※ 引述《topee (eason)》之銘言:
: [u(t)-u(t-1)]t^2
: 拉氏轉換
:
這樣可行??
= e^-0s L[t^2] - e^-s L[t^2]
t=t-0 t = t+1
= e^-0s L[t^2] - e^-s L[(t+1)^2]
2 2 2 1
= ----- - [----- + ----- + ---]e^-s
s^3 s^3 s^2 s
I大是這樣做嗎?
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※ 編輯: topee 來自: 125.228.221.105 (03/31 23:29)
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