![](https://i.imgur.com/nVWhs1w.jpg)
Re: [微積] 大學微積分
![](https://i.imgur.com/nVWhs1w.jpg)
h
∫dh/√(h + L)
H
令u = h + L
h+L
= ∫ du / √u
H+L
h+L
= 2√u |
H+L
= 2[√(h + L) - √(H + L)]
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